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Question
Find the equation of a line that cuts off equal intercepts on the coordinate axes and passes through the point (2, 3).
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Solution
Line AB passes through the point P(2, 3) and makes equal intercepts on the coordinate axes.
OA = OB
∠BAO = 45°,
∠BAX = 135°
Slope of AB, m = tan 135° = –1
Equation of line, y – y1 = m(x – x1)
Where x1 = 2, Y1 = 3 and m = –1
y – 3 = – (x – 2)
or x + y – 5 = 0
or x + y = 5
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