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Find the equation for the ellipse that satisfies the given conditions: Vertices (±6, 0), foci (±4, 0)

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Question

Find the equation for the ellipse that satisfies the given conditions:

Vertices (±6, 0), foci (±4, 0)

Sum
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Solution

Vertices (±6, 0), foci (±4, 0)

Here, the vertices are on the x-axis.

Therefore, the equation of the ellipse will be of the form `x^2/a^2 + y^2/b^2` = 1, where a is the semi-major axis.

Accordingly, a = 6 and c = 4

It is known that a2 = b2 + c2

∴ 62 = b2 + 42

= 36 = b2 + 16

= b2 = 36 - 16

= b = `sqrt20`

Thus, the equation of the ellipse is `x^2/6^2 + y^2/(sqrt(20))^2 = 1` or `x^2/36 + y^2/20 = 1`.

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Chapter 10: Conic Sections - EXERCISE 10.3 [Page 195]

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NCERT Mathematics [English] Class 11
Chapter 10 Conic Sections
EXERCISE 10.3 | Q 12. | Page 195
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