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Find the differential equation of the family of curves y = Ae2x + B.e–2x. - Mathematics

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Question

Find the differential equation of the family of curves y = Ae2x + B.e–2x.

Sum
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Solution

y = Ae2x + B.e–2x.

`("d"y)/("d"x) = 2"Ae"^(2x) - 2"B"e"^(-2x)` and `("d"^2y)/("dx"^2) = 4"Ae"^(2x) + 4"Be"^(-2x)`

Thus `("d"^2y)/("dx"^2) = 4y`

i.e., `("d"^2y)/("dx"^2) - 4y` = 0.

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Chapter 9: Differential Equations - Solved Examples [Page 180]

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NCERT Exemplar Mathematics [English] Class 12
Chapter 9 Differential Equations
Solved Examples | Q 1 | Page 180

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