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Question
Find the derivative of the function y = f(x) using the derivative of the inverse function x = f–1(y) in the following:
y = log(2x – 1)
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Solution
y = log(2x – 1) ...(1)
We have to find the inverse function of y = f(x), i.e x in terms of y.
From (1),
2x – 1 = ey
∴ 2x = ey + 1
∴ x = f–1(y)
= `(1)/(2)(e^y + 1)`
∴ `"dx"/"dy" = (1)/(2)"d"/"dy"(e^y + 1)`
= `(1)/(2)(e^y + 0)`
= `(1)/(2)e^y`
= `(1)/(2)e^(log(2x - 1)` ...[By (1)]
= `(1)/(2)(2x - 1)` ...[∵ elogx = x]
∴ `"dy"/"dx" = (1)/(("dx"/"dy")`
= `(2)/(2x - 1)`
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