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Question
Find the area of the shaded region given in figure
Sum
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Solution
ABCD is a square of side 14 cm.
Join JK, KL, LM and MJ.
There are four equal semi-circles and JKLM formed a square.
∴ FH = 14 – (3 + 3) = 8 cm
So, the side of square JKLM is 4 cm and radius of semi-circle of both ends are 2 cm each.
∴ Area of square JKLM = (4)2 = 16 cm2
Area of semi-circle HJM = `(π"r"^2)/2`
= `(π xx (2)^2)/2`
= 2π cm2
∴ Area of four semi-circles
= 4 × 2π
= 8π cm2
Now, area of square ABCD = (14)2 cm2 = 196 cm2
∴ Area of shaded region = Area of square
ABCD – [Area of four semi-circles + Area of square JKLM]
= 196 – [8π + 16]
= 196 – 16 – 8π
= (180 – 8π) cm2
Hence, the required area of the shaded region is (180 – 8π) cm2.
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