Question

Find the 8 th term of the G.p. `sqrt3, 1/sqrt3, 1/(3sqrt3)`, .... 

Answer 1

a = `sqrt3`

r = `(1/sqrt3)/sqrt3`

= `1/3`

`a_n = ar^(n - 1)`

`a_8 = ar^(8 - 1)`

a₈ = ar⁷

a₈ = `sqrt3 xx (1/3)^7`

a₈ = `sqrt3 xx 1/sqrt3^14`

a₈ = `1/(729sqrt3)`

a₈ = `sqrt3/2187`