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Question
Find the 4th vertex of a parallelogram if three vertices taken in order are (−5, −5) (2, −3), and (4, 4).
Sum
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Solution
Here, let,
- A = (−5, −5),
- B = (2, −3),
- C = (4, 4)
In a parallelogram ABCD (vertices in order), D = A + (C − B),
⇒ C − B = (4, 4) − (2, −3)
= (4 − 2, 4 − (−3))
= (2, 7)
⇒ A + D = (−5, −5) + (2, 7)
= (−5 + 2, −5 + 7)
= (−3, 2)
Hence, the fourth vertex is (−3, 2).
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