Question

Find the 22nd term of the progression `7 3/4 + 9 1/2 + 11 1/4 + ...`

Answer 1

a₁ = `7 3/4`

= `31/4`

d = `9 1/2 − 7 3/4`

d = `9 (1 xx 2)/(2 xx 2) - 7 3/4`

d = `9 2/4 - 7 3/4`

d = `38/4 - 31/4`

d = `7/4`

a₂₂ = a₁ + 21 × d

= `31/4 + 21 xx (7/4)`

= `(31 + 147)/4`

= `178/4 = 89/2`

= `44 1/2`