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Question
Find the square root of:
\[38\frac{11}{25}\]
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Solution
We know:
\[\sqrt{38\frac{11}{25}} = \sqrt{\frac{961}{25}} = \frac{\sqrt{961}}{\sqrt{25}}\]
Now, let us compute the square roots of the numerator and the denominator separately.
\[\sqrt{961} = 31\]
\[\sqrt{25} = 5\]
\[ \therefore \sqrt{38\frac{11}{25}} = \frac{31}{5}\]
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