Advertisements
Advertisements
Question
Find the remainder when x3 – ax2 + 6x – a is divided by x – a.
Advertisements
Solution 1
Let p(x) = x3 – ax2 + 6x – a
x - a = 0
∴ x = a
∴ Remainder = (a)3 - a(a)2 + 6(a) - a
= a3 - a3 + 6a - a
= 5a
Therefore, the remainder obtained is 5a.
Solution 2
By long division,

Therefore, when x3 − ax2 + 6x − a is divided by x − a, the remainder obtained is 5a.
APPEARS IN
RELATED QUESTIONS
Find the remainder when x3 + 3x2 + 3x + 1 is divided by x.
Find the remainder when x3 + 3x2 + 3x + 1 is divided by x + π.
Find the remainder when x4 + 1 is divided by x + 1.
Using the Remainder Theorem, factorise the expression 3x3 + 10x2 + x – 6. Hence, solve the equation 3x3 + 10x2 + x – 6 = 0
Find the values of p and q in the polynomial f(x)= x3 - px2 + 14x -q, if it is exactly divisible by (x-1) and (x-2).
Find the values of a and b when the factors of the polynomial f(x)= ax3 + bx2 + x a are (x+3) and (2x-1). Factorize the polynomial completely.
Find the remainder (without division) on dividing 3x2 + 5x – 9 by (3x + 2)
Use the Remainder Theorem to factorise the following expression:
2x3 + x2 – 13x + 6
When a polynomial f(x) is divided by (x – 1), the remainder is 5 and when it is,, divided by (x – 2), the remainder is 7. Find – the remainder when it is divided by (x – 1) (x – 2).
Determine which of the following polynomials has x – 2 a factor:
4x2 + x – 2
