Advertisements
Advertisements
प्रश्न
Find the remainder when x3 – ax2 + 6x – a is divided by x – a.
Advertisements
उत्तर १
Let p(x) = x3 – ax2 + 6x – a
x - a = 0
∴ x = a
∴ Remainder = (a)3 - a(a)2 + 6(a) - a
= a3 - a3 + 6a - a
= 5a
Therefore, the remainder obtained is 5a.
उत्तर २
By long division,
Therefore, when x3 − ax2 + 6x − a is divided by x − a, the remainder obtained is 5a.
संबंधित प्रश्न
Find the remainder when x3 + 3x2 + 3x + 1 is divided by x + π.
Use the Remainder Theorem to factorise the following expression:]
`2x^3 + x^2 - 13x + 6`
Using the Remainder Theorem, factorise the following completely:
4x3 + 7x2 – 36x – 63
Using the Remainder Theorem, factorise the expression 3x3 + 10x2 + x – 6. Hence, solve the equation 3x3 + 10x2 + x – 6 = 0
When divided by x – 3 the polynomials x3 – px2 + x + 6 and 2x3 – x2 – (p + 3) x – 6 leave the same remainder. Find the value of ‘p’.
use the rernainder theorem to find the factors of ( a-b )3 + (b-c )3 + ( c-a)3
By remainder theorem, find the remainder when, p(x) is divided by g(x) where, p(x) = 4x3 – 12x2 + 14x – 3; g(x) = 2x – 1
Find the remainder when 3x3 – 4x2 + 7x – 5 is divided by (x + 3)
By Remainder Theorem find the remainder, when p(x) is divided by g(x), where p(x) = x3 – 6x2 + 2x – 4, g(x) = `1 - 3/2 x`
For what value of m is x3 – 2mx2 + 16 divisible by x + 2?
