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Karnataka Board PUCPUC Science Class 11

Find the Radius of Gyration of Circular Ring of Radius R About a Line Perpendicular to the Plane of the Ring and Passing Through One of Its Particles.

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Question

Find the radius of gyration of circular ring of radius r about a line perpendicular to the plane of the ring and passing through one of its particles.

Sum
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Solution

Moment of inertia of the ring about a point on the rim of the ring and the axis perpendicular to the plane of the ring = mR2 + mR2 = 2mR2 (from parallel axis theorem)

We know that

\[m K^2 = 2m R^2 \]

K = Radius of the gyration

\[ \Rightarrow K = \sqrt{2 R^2} = \sqrt{2}R\]

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Chapter 10: Rotational Mechanics - Exercise [Page 196]

APPEARS IN

HC Verma Concepts of Physics Volume 1 and 2 [English]
Chapter 10 Rotational Mechanics
Exercise | Q 13 | Page 196

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