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Question
Find out the wavelength of the electron orbiting in the ground state of hydrogen atom.
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Solution
Radius of ground state of hydrogen atom
= 0.53 Å = 0.53 x 10-10 m
According to de Brogile relation
2πr = nλ
For ground state n = 1
2 x 3.14 x 0.53 x 10-10 = 1 x λ
∴ λ = 3.32 x 10-10 m
= 3.32 Å
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| List-I (Spectral Lines of Hydrogen for transitions from) |
List-II (Wavelengths (nm)) |
||
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| B. | n2 = 4 to n1 = 2 | II. | 434.1 |
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