Question

Find the minimum energy of neutron confined to a nucleus of size of the order of 10^-14m. Given mass of neutron = 1.675×10^-27kg 

Answer 1

Given data :- L=10^-14 m  
Formula :- `E_n = n^2 (h^2/(8ml^2))…………………….(n = 1,2,3…..)`
Solution :- `E_n= n^2 (h^2/(8mL^2) ) = ((6.63×10^-34 )×(6.63×10^-34 )) / (8×1.67×10^-27 xx (10 ^-14 ) ^2) ` ........(n = 1)
`E_1 =3.29×10^-13J`
Lower energy = 3.29×10^-13 J