Advertisements
Advertisements
Question
Find the median of the following frequency distribution :
| Salarv fin Rs) | 3500 | 4000 | 4500 | 5000 | 5500 | 6000 |
| No. of people | 9 | 17 | 23 | 15 | 6 | 5 |
Sum
Advertisements
Solution
| Salary (in Rs) | No. of students (f) | Cumulative frequency |
| 3500 | 9 | 9 |
| 4000 | 17 | 26 |
| 4500 | 23 | 49 |
| 5000 | 15 | 64 |
| 5500 | 6 | 70 |
| 6000 | 5 | 75 |
No. of terms = 75
median = `(75 + 1)/2` = 38th term
38th term lies under 4500
Hence, Median = 4500
shaalaa.com
Is there an error in this question or solution?
