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Find the Mean and Standard Deviation of Each of the Following Probability Distribution : Xi : 0 1 2 3 4 5 Pi : 1 6 5 18 2 9 1 6 1 9 1 18 - Mathematics

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Question

Find the mean and standard deviation of each of the following probability distribution :

xi :  0 1 2 3 4 5
pi : 
\[\frac{1}{6}\]
\[\frac{5}{18}\]
\[\frac{2}{9}\]
\[\frac{1}{6}\]
\[\frac{1}{9}\]
\[\frac{1}{18}\]
Sum
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Solution

xi pi pixi pixi2
0
\[\frac{1}{6}\]
0 0
1
\[\frac{5}{18}\]
\[\frac{5}{18}\]
\[\frac{5}{18}\]
2
\[\frac{2}{9}\]
\[\frac{4}{9}\]
\[\frac{8}{9}\]
3
\[\frac{1}{6}\]
\[\frac{1}{2}\]
\[\frac{3}{2}\]
4
\[\frac{1}{9}\]
\[\frac{4}{9}\]
\[\frac{16}{9}\]
5
\[\frac{1}{18}\]
\[\frac{5}{18}\]
\[\frac{25}{18}\]
    `∑`pixi =
\[\frac{35}{18}\]
`∑`pixi2=
\[\frac{35}{6}\]

\[\text{ Mean}  = \sum p_i x_i = \frac{35}{18}\]
\[\text{ Variance } = \sum p_i {x_i}^2 - \left( \text{ Mean } \right)^2 \]
\[ = \frac{35}{6} - \left( \frac{35}{18} \right)^2 \]
\[ = \frac{35}{6} - \frac{1225}{324}\]
\[ = \frac{1890 - 1225}{324}\]
\[ = \frac{665}{324}\]
\[\text{ Step Deviation } = \sqrt{\text{ Variance } }\]
\[ = \sqrt{\frac{665}{324}}\]
\[ = \frac{\sqrt{665}}{18}\]

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Chapter 32: Mean and Variance of a Random Variable - Exercise 32.2 [Page 42]

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RD Sharma Mathematics [English] Class 12
Chapter 32 Mean and Variance of a Random Variable
Exercise 32.2 | Q 1.9 | Page 42
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