Question

Find mean for the following probability distribution.

X	0	1	2	3
P(X = x)	`1/6`	`1/3`	`1/3`	`1/6`

Answer 1

Mean of the given distribution is

E(X) = `sumx_"i"  "P"(x_"i")`

= `0(1/6) + 1(1/3) + 2(1/3) + 3(1/6)`

= `0 + 1/3 + 2/3 + 1/2`

= `3/2`