Question

Find the length of the shadow cast by a tree 60 m high when the sun's altitude is `30^circ`.

Answer 1

Let AB be the tree of height 60 m and BC be its shadow .

In ΔABC

`"AB"/"BC"` = `tan30^circ`

`60/"BC" = 1/sqrt(3)`

`"BC" = 60sqrt(3)` m

So , height of tower is `60sqrt(3)` m .