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Question
Find: `int(3x-1)/(sqrt(x^2-4x))dx`
Sum
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Solution
`int(3x-1)/(sqrt(x^2-4x))dx`
= `int(3/2(2x-4)+5)/(sqrt(x^2-4x))dx`
= `3/2int(2x-4)/(sqrt(x^2-4x))dx+5int1/(sqrt(x^2-4x+2^2-2^2))dx`
= `3/2sqrt(x^2-4x)+5int1/(sqrt((x-2^2))-2^2)dx`
= `3sqrt(x^2-4x)+5log|(x-2)+sqrt(x^2-4x)|+C`
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