Question

Find the general solution of the equation `4cos^2x=1`

Answer 1

Given:

`4cos^2x=1`

`cos^2x=1/4`

`cos^2x=cos^2(pi/3)`

`["Using " cos^2x=cos^2alpha => x=npi+-alpha]`

`x=npi+-pi/3" where " n in Z`