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Question
Find \[\frac{dy}{dx}\] if \[y+\sin y=\cos x\].
Options
\[-\frac{\sin x}{1+\cos y}\]
\[\frac{\sin x}{1+\cos y}\]
\[-\frac{\cos x}{1+\sin y}\]
\[-\sin x(1+\cos y)\]
MCQ
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Solution
Differentiation gives \[\frac{dy}{dx}+\cos y\cdot\frac{dy}{dx}=-\sin x\]. Factoring \[\frac{dy}{dx}\] gives \[(1+\cos y)\frac{dy}{dx}=-\sin x\], so the stated derivative follows.
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