Question

Find the following product:
−11y²(3y + 7)

Answer 1

To find the product, we will use distributive law as follows:

\[- 11 y^2 \left( 3y + 7 \right)\]

\[ = \left( - 11 y^2 \right) \times 3y + \left( - 11 y^2 \right) \times 7\]

\[ = \left( - 11 \times 3 \right)\left( y^2 \times y \right) + \left( - 11 \times 7 \right) \times \left( y^2 \right)\]

\[ = \left( - 33 \right)\left( y^{2 + 1} \right) + \left( - 77 \right) \times \left( y^2 \right)\]

\[ = - 33 y^3 - 77 y^2\] 

Thus, the answer is \[- 33 y^3 - 77 y^2\] .