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प्रश्न
Find the following product:
−11y2(3y + 7)
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उत्तर
To find the product, we will use distributive law as follows:
\[- 11 y^2 \left( 3y + 7 \right)\]
\[ = \left( - 11 y^2 \right) \times 3y + \left( - 11 y^2 \right) \times 7\]
\[ = \left( - 11 \times 3 \right)\left( y^2 \times y \right) + \left( - 11 \times 7 \right) \times \left( y^2 \right)\]
\[ = \left( - 33 \right)\left( y^{2 + 1} \right) + \left( - 77 \right) \times \left( y^2 \right)\]
\[ = - 33 y^3 - 77 y^2\]
Thus, the answer is \[- 33 y^3 - 77 y^2\] .
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