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प्रश्न
Find the following product:
−11y2(3y + 7)
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उत्तर
To find the product, we will use distributive law as follows:
\[- 11 y^2 \left( 3y + 7 \right)\]
\[ = \left( - 11 y^2 \right) \times 3y + \left( - 11 y^2 \right) \times 7\]
\[ = \left( - 11 \times 3 \right)\left( y^2 \times y \right) + \left( - 11 \times 7 \right) \times \left( y^2 \right)\]
\[ = \left( - 33 \right)\left( y^{2 + 1} \right) + \left( - 77 \right) \times \left( y^2 \right)\]
\[ = - 33 y^3 - 77 y^2\]
Thus, the answer is \[- 33 y^3 - 77 y^2\] .
संबंधित प्रश्न
Find each of the following product:
−3a2 × 4b4
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(3x) × (4x) × (−5x)
Express each of the following product as a monomials and verify the result in each case for x = 1:
(4x2) × (−3x) × \[\left( \frac{4}{5} x^3 \right)\]
Evaluate each of the following when x = 2, y = −1.
\[(2xy) \times \left( \frac{x^2 y}{4} \right) \times \left( x^2 \right) \times \left( y^2 \right)\]
Find the following product: \[- \frac{8}{27}xyz\left( \frac{3}{2}xy z^2 - \frac{9}{4}x y^2 z^3 \right)\]
Simplify: a2(2a − 1) + 3a + a3 − 8
Multiply:
(x2 + y2) by (3a + 2b)
Simplify:
(x3 − 2x2 + 5x − 7)(2x − 3)
Simplify:
(3x + 2y)(4x + 3y) − (2x − y)(7x − 3y)
What is the product of 3x and 4x²?
