Advertisements
Advertisements
प्रश्न
Find the following product: \[\frac{6x}{5}( x^3 + y^3 )\]
Advertisements
उत्तर
To find the product, we will use distributive law as follows:
\[\frac{6x}{5}\left( x^3 + y^3 \right)\]
\[ = \frac{6x}{5} \times x^3 + \frac{6x}{5} \times y^3 \]
\[ = \frac{6}{5} \times \left( x \times x^3 \right) + \frac{6}{5} \times \left( x \times y^3 \right)\]
\[ = \frac{6}{5} \times \left( x^{1 + 3} \right) + \frac{6}{5} \times \left( x \times y^3 \right)\]
\[ = \frac{6 x^4}{5} + \frac{6x y^3}{5}\]
Thus, the answer is \[\frac{6 x^4}{5} + \frac{6x y^3}{5}\].
APPEARS IN
संबंधित प्रश्न
Express each of the following product as a monomials and verify the result in each case for x = 1:
(4x2) × (−3x) × \[\left( \frac{4}{5} x^3 \right)\]
Find the following product: \[\left( - \frac{7}{4}a b^2 c - \frac{6}{25} a^2 c^2 \right)( - 50 a^2 b^2 c^2 )\]
Find the following product: \[\frac{4}{3}a( a^2 + b^2 - 3 c^2 )\]
Simplify: a2b(a3 − a + 1) − ab(a4 − 2a2 + 2a) − b (a3 − a2 − 1)
Multiply:
(3x2 + y2) by (2x2 + 3y2)
Multiply: \[\left( \frac{3}{5}x + \frac{1}{2}y \right) by \left( \frac{5}{6}x + 4y \right)\]
Simplify:
x2(x − y) y2(x + 2y)
Simplify:
(5 − x)(6 − 5x)( 2 − x)
Simplify : (x − y)(x + y) (x2 + y2)(x4 + y2)
What is the product of 3x and 4x²?
