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प्रश्न
Find the following product: \[\frac{6x}{5}( x^3 + y^3 )\]
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उत्तर
To find the product, we will use distributive law as follows:
\[\frac{6x}{5}\left( x^3 + y^3 \right)\]
\[ = \frac{6x}{5} \times x^3 + \frac{6x}{5} \times y^3 \]
\[ = \frac{6}{5} \times \left( x \times x^3 \right) + \frac{6}{5} \times \left( x \times y^3 \right)\]
\[ = \frac{6}{5} \times \left( x^{1 + 3} \right) + \frac{6}{5} \times \left( x \times y^3 \right)\]
\[ = \frac{6 x^4}{5} + \frac{6x y^3}{5}\]
Thus, the answer is \[\frac{6 x^4}{5} + \frac{6x y^3}{5}\].
संबंधित प्रश्न
Evaluate each of the following when x = 2, y = −1.
\[\left( \frac{3}{5} x^2 y \right) \times \left( - \frac{15}{4}x y^2 \right) \times \left( \frac{7}{9} x^2 y^2 \right)\]
Find the product 24x2 (1 − 2x) and evaluate its value for x = 3.
Simplify: a(b − c) + b(c − a) + c(a − b)
Multiply: \[\left( \frac{3}{5}x + \frac{1}{2}y \right) by \left( \frac{5}{6}x + 4y \right)\]
Multiply:
(x2 + y2) by (3a + 2b)
Simplify:
a2b2(a + 2b)(3a + b)
Simplify:
x2(x − y) y2(x + 2y)
Simplify:
(3x − 2)(2x − 3) + (5x − 3)(x + 1)
Simplify : (2x − 1)(2x + 1)(4x2 + 1)(16x4 + 1)
What is the product of (x + 3) and (x − 5)?
