Advertisements
Advertisements
प्रश्न
Find each of the following product: \[\left( \frac{- 24}{25} x^3 z \right) \times \left( - \frac{15}{16}x z^2 y \right)\]
Advertisements
उत्तर
To multiply algebraic expressions, we use commutative and associative laws along with the law of indices, i.e., \[a^m \times a^n = a^{m + n}\].
We have:
\[\left( - \frac{24}{25} x^3 z \right) \times \left( - \frac{15}{16}x z^2 y \right)\]
\[ = \left\{ \left( - \frac{24}{25} \right) \times \left( - \frac{15}{16} \right) \right\} \times \left( x^3 \times x \right) \times \left( z \times z^2 \right) \times y\]
\[ = \left\{ \left( - \frac{24}{25} \right) \times \left( - \frac{15}{16} \right) \right\} \times \left( x^{3 + 1} \right) \times \left( z^{1 + 2} \right) \times y\]
\[= \frac{9}{10} x^4 y z^3\]
Thus, the answer is \[\frac{9}{10} x^4 y z^3\].
संबंधित प्रश्न
Find each of the following product:
(−5xy) × (−3x2yz)
Find each of the following product:
\[\left( - \frac{1}{27} a^2 b^2 \right) \times \left( \frac{9}{2} a^3 b^2 c^2 \right)\]
Find the product 24x2 (1 − 2x) and evaluate its value for x = 3.
Simplify: 4ab(a − b) − 6a2(b − b2) − 3b2(2a2 − a) + 2ab(b − a)
Simplify: a2(2a − 1) + 3a + a3 − 8
Multiply:
(2x2 − 1) by (4x3 + 5x2)
Find the following product and verify the result for x = − 1, y = − 2:
(3x − 5y) (x + y)
Find the following product and verify the result for x = − 1, y = − 2:
(x2y − 1) (3 − 2x2y)
Simplify:
(3x − 2)(2x − 3) + (5x − 3)(x + 1)
Show that: (a − b)(a + b) + (b − c)(b + c) + (c − a)( c + a) = 0
