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प्रश्न
Find each of the following product:
\[\left( - \frac{1}{27} a^2 b^2 \right) \times \left( \frac{9}{2} a^3 b^2 c^2 \right)\]
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उत्तर
To multiply algebraic expressions, we use commutative and associative laws along with the law of indices, i.e.,
\[\left( - \frac{1}{27} a^2 b^2 \right) \times \left( \frac{9}{2} a^3 b^2 c^2 \right)\]
\[ = \left( - \frac{1}{27} \times \frac{9}{2} \right) \times \left( a^2 \times a^3 \right) \times \left( b^2 \times b^2 \right) \times c^2 \]
\[ = \left( - \frac{1}{27} \times \frac{9}{2} \right) \times \left( a^{2 + 3} \right) \times \left( b^{2 + 2} \right) \times c^2 \]
\[ = - \frac{1}{6} a^5 b^4 c^2\]
Thus, the answer is \[- \frac{1}{6} a^5 b^4 c^2\].
संबंधित प्रश्न
Find each of the following product:
\[\left( - \frac{2}{7} a^4 \right) \times \left( - \frac{3}{4} a^2 b \right) \times \left( - \frac{14}{5} b^2 \right)\]
Evaluate (−8x2y6) × (−20xy) for x = 2.5 and y = 1.
Find the following product:
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(2x + 8) by (x − 3)
(2xy + 3y2) (3y2 − 2)
Simplify:
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Solve:
(3x + 2y)(7x − 8y)
