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प्रश्न
Find each of the following product:
\[\left( - \frac{1}{27} a^2 b^2 \right) \times \left( \frac{9}{2} a^3 b^2 c^2 \right)\]
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उत्तर
To multiply algebraic expressions, we use commutative and associative laws along with the law of indices, i.e.,
\[\left( - \frac{1}{27} a^2 b^2 \right) \times \left( \frac{9}{2} a^3 b^2 c^2 \right)\]
\[ = \left( - \frac{1}{27} \times \frac{9}{2} \right) \times \left( a^2 \times a^3 \right) \times \left( b^2 \times b^2 \right) \times c^2 \]
\[ = \left( - \frac{1}{27} \times \frac{9}{2} \right) \times \left( a^{2 + 3} \right) \times \left( b^{2 + 2} \right) \times c^2 \]
\[ = - \frac{1}{6} a^5 b^4 c^2\]
Thus, the answer is \[- \frac{1}{6} a^5 b^4 c^2\].
संबंधित प्रश्न
Find each of the following product: \[( - 7xy) \times \left( \frac{1}{4} x^2 yz \right)\]
Find each of the following product: \[\left( \frac{7}{9}a b^2 \right) \times \left( \frac{15}{7}a c^2 b \right) \times \left( - \frac{3}{5} a^2 c \right)\]
Express each of the following product as a monomials and verify the result in each case for x = 1:
(4x2) × (−3x) × \[\left( \frac{4}{5} x^3 \right)\]
Evaluate each of the following when x = 2, y = −1.
\[(2xy) \times \left( \frac{x^2 y}{4} \right) \times \left( x^2 \right) \times \left( y^2 \right)\]
Find the product −3y(xy + y2) and find its value for x = 4 and y = 5.
Multiply:
(7x + y) by (x + 5y)
Simplify:
(2x2 + 3x − 5)(3x2 − 5x + 4)
Show that: \[\left( \frac{4m}{3} - \frac{3n}{4} \right)^2 + 2mn = \frac{16 m^2}{9} + \frac{9 n^2}{16}\]
Multiply:
(12a + 17b) × 4c
Solve:
(3x + 2y)(7x − 8y)
