Advertisements
Advertisements
प्रश्न
Simplify:
(2x2 + 3x − 5)(3x2 − 5x + 4)
Advertisements
उत्तर
To simplify, we will proceed as follows:
\[\left( 2 x^2 + 3x - 5 \right)\left( 3 x^2 - 5x + 4 \right)\]
\[= 2 x^2 \left( 3 x^2 - 5x + 4 \right) + 3x\left( 3 x^2 - 5x + 4 \right) - 5\left( 3 x^2 - 5x + 4 \right)\] (Distributive law)
\[= 6 x^4 - 10 x^3 + 8 x^2 + 9 x^3 - 15 x^2 + 12x - 15 x^2 + 25x - 20\]
\[= 6 x^4 - 10 x^3 + 9 x^3 + 8 x^2 - 15 x^2 - 15 x^2 + 12x + 25x - 20\] (Rearranging)
\[= 6 x^4 - x^3 - 22 x^2 + 36x - 20\] (Combining like terms)
Thus, the answer is \[6 x^4 - x^3 - 22 x^2 + 36x - 20\].
APPEARS IN
संबंधित प्रश्न
Find each of the following product:
(−5xy) × (−3x2yz)
Find each of the following product:
\[\left( - \frac{7}{5}x y^2 z \right) \times \left( \frac{13}{3} x^2 y z^2 \right)\]
Find each of the following product: \[( - 7xy) \times \left( \frac{1}{4} x^2 yz \right)\]
Express each of the following product as a monomials and verify the result in each case for x = 1:
(3x) × (4x) × (−5x)
Simplify: x2(x2 + 1) − x3(x + 1) − x(x3 − x)
Multiply:
(x6 − y6) by (x2 + y2)
Multiply:
(2x2y2 − 5xy2) by (x2 − y2)
Show that: (4pq + 3q)2 − (4pq − 3q)2 = 48pq2
Multiply:
(4x + 5y) × (9x + 7y)
Solve the following equation.
5(x + 1) = 74
