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प्रश्न
Find each of the following product: \[\left( \frac{- 24}{25} x^3 z \right) \times \left( - \frac{15}{16}x z^2 y \right)\]
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उत्तर
To multiply algebraic expressions, we use commutative and associative laws along with the law of indices, i.e., \[a^m \times a^n = a^{m + n}\].
We have:
\[\left( - \frac{24}{25} x^3 z \right) \times \left( - \frac{15}{16}x z^2 y \right)\]
\[ = \left\{ \left( - \frac{24}{25} \right) \times \left( - \frac{15}{16} \right) \right\} \times \left( x^3 \times x \right) \times \left( z \times z^2 \right) \times y\]
\[ = \left\{ \left( - \frac{24}{25} \right) \times \left( - \frac{15}{16} \right) \right\} \times \left( x^{3 + 1} \right) \times \left( z^{1 + 2} \right) \times y\]
\[= \frac{9}{10} x^4 y z^3\]
Thus, the answer is \[\frac{9}{10} x^4 y z^3\].
संबंधित प्रश्न
Find each of the following product:
\[\left( - \frac{1}{27} a^2 b^2 \right) \times \left( \frac{9}{2} a^3 b^2 c^2 \right)\]
Find the following product: \[\left( - \frac{7}{4}a b^2 c - \frac{6}{25} a^2 c^2 \right)( - 50 a^2 b^2 c^2 )\]
Simplify: a2(2a − 1) + 3a + a3 − 8
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[−3d + (−7f)] by (5d + f)
Simplify:
x2(x − y) y2(x + 2y)
Simplify:
(x3 − 2x2 + 5x − 7)(2x − 3)
Simplify:
(5x + 3)(x − 1)(3x − 2)
Show that: (a − b)(a + b) + (b − c)(b + c) + (c − a)( c + a) = 0
Multiply:
(4x + 5y) × (9x + 7y)
Solve the following equation.
6x − 1 = 3x + 8
