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प्रश्न
Find the product 24x2 (1 − 2x) and evaluate its value for x = 3.
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उत्तर
To find the product, we will use distributive law as follows:
\[24 x^2 \left( 1 - 2x \right)\]
\[ = 24 x^2 \times 1 - 24 x^2 \times 2x\]
\[ = 24 x^2 - 48 x^{1 + 2} \]
\[ = 24 x^2 - 48 x^3\]
Substituting x = 3 in the result, we get:
\[24 x^2 - 48 x^3 \]
\[ = 24 \left( 3 \right)^2 - 48 \left( 3 \right)^3 \]
\[ = 24 \times 9 - 48 \times 27\]
\[ = 216 - 1296\]
\[ = - 1080\]
Thus, the product is \[(24 x^2 - 48 x^3 )\text {P and its value for x = 3 is } ( - 1080)\].
संबंधित प्रश्न
Find each of the following product:
\[\frac{1}{4}xy \times \frac{2}{3} x^2 y z^2\]
Evaluate each of the following when x = 2, y = −1.
\[(2xy) \times \left( \frac{x^2 y}{4} \right) \times \left( x^2 \right) \times \left( y^2 \right)\]
Find the following product: \[- \frac{4}{27}xyz\left( \frac{9}{2} x^2 yz - \frac{3}{4}xy z^2 \right)\]
Simplify: a2(2a − 1) + 3a + a3 − 8
Multiply:
(2x2y2 − 5xy2) by (x2 − y2)
Multiply:
(3x2y − 5xy2) by \[\left( \frac{1}{5} x^2 + \frac{1}{3} y^2 \right)\].
Find the following product and verify the result for x = − 1, y = − 2:
(3x − 5y) (x + y)
Simplify:
x2(x − y) y2(x + 2y)
Simplify:
(5 − x)(6 − 5x)( 2 − x)
Simplify:
(3x + 2y)(4x + 3y) − (2x − y)(7x − 3y)
