Advertisements
Advertisements
प्रश्न
Find the product 24x2 (1 − 2x) and evaluate its value for x = 3.
Advertisements
उत्तर
To find the product, we will use distributive law as follows:
\[24 x^2 \left( 1 - 2x \right)\]
\[ = 24 x^2 \times 1 - 24 x^2 \times 2x\]
\[ = 24 x^2 - 48 x^{1 + 2} \]
\[ = 24 x^2 - 48 x^3\]
Substituting x = 3 in the result, we get:
\[24 x^2 - 48 x^3 \]
\[ = 24 \left( 3 \right)^2 - 48 \left( 3 \right)^3 \]
\[ = 24 \times 9 - 48 \times 27\]
\[ = 216 - 1296\]
\[ = - 1080\]
Thus, the product is \[(24 x^2 - 48 x^3 )\text {P and its value for x = 3 is } ( - 1080)\].
APPEARS IN
संबंधित प्रश्न
Find each of the following product:
\[\left( - \frac{7}{5}x y^2 z \right) \times \left( \frac{13}{3} x^2 y z^2 \right)\]
Find each of the following product:
(−5a) × (−10a2) × (−2a3)
Find each of the following product: \[\left( \frac{4}{3} u^2 vw \right) \times \left( - 5uv w^2 \right) \times \left( \frac{1}{3} v^2 wu \right)\]
Find each of the following product:
\[\left( 0 . 5x \right) \times \left( \frac{1}{3}x y^2 z^4 \right) \times \left( 24 x^2 yz \right)\]
Express each of the following product as a monomials and verify the result in each case for x = 1:
(5x4) × (x2)3 × (2x)2
Find the following product: \[- \frac{4}{27}xyz\left( \frac{9}{2} x^2 yz - \frac{3}{4}xy z^2 \right)\]
Simplify: x3y(x2 − 2x) + 2xy(x3 − x4)
Simplify: a2(2a − 1) + 3a + a3 − 8
Multiply:
(4x + 5y) × (9x + 7y)
What is the product of (x + 3) and (x − 5)?
