Advertisements
Advertisements
प्रश्न
Find each of the following product:
\[\left( 0 . 5x \right) \times \left( \frac{1}{3}x y^2 z^4 \right) \times \left( 24 x^2 yz \right)\]
Advertisements
उत्तर
To multiply algebraic expressions, we use commutative and associative laws along with the law of indices, i.e., \[a^m \times a^n = a^{m + n}\].
We have:
\[\left( 0 . 5x \right) \times \left( \frac{1}{3}x y^2 z^4 \right) \times \left( 24 x^2 yz \right)\]
\[ = \left( 0 . 5 \times \frac{1}{3} \times 24 \right) \times \left( x \times x \times x^2 \right) \times \left( y^2 \times y \right) \times \left( z^4 \times z \right)\]
\[ = \left( 0 . 5 \times \frac{1}{3} \times 24 \right) \times \left( x^{1 + 1 + 2} \right) \times \left( y^{2 + 1} \right) \times \left( z^{4 + 1} \right)\]
\[ = 4 x^4 y^3 z^5\]
Thus, the answer is \[4 x^4 y^3 z^5\].
APPEARS IN
संबंधित प्रश्न
Find each of the following product:
(2.3xy) × (0.1x) × (0.16)
Express each of the following product as a monomials and verify the result in each case for x = 1:
(3x) × (4x) × (−5x)
Express each of the following product as a monomials and verify the result in each case for x = 1:
(4x2) × (−3x) × \[\left( \frac{4}{5} x^3 \right)\]
Find the value of (5x6) × (−1.5x2y3) × (−12xy2) when x = 1, y = 0.5.
Evaluate (2.3a5b2) × (1.2a2b2) when a = 1 and b = 0.5.
Find the following product: \[\frac{6x}{5}( x^3 + y^3 )\]
Simplify: a2b(a − b2) + ab2(4ab − 2a2) − a3b(1 − 2b)
Multiply: \[\left( \frac{3}{5}x + \frac{1}{2}y \right) by \left( \frac{5}{6}x + 4y \right)\]
Multiply:
(4x + 5y) × (9x + 7y)
What is the result of 2y(3y² − 4y + 5)?
