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प्रश्न
Find the product −3y(xy + y2) and find its value for x = 4 and y = 5.
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उत्तर
To find the product, we will use distributive law as follows:
\[- 3y\left( xy + y^2 \right)\]
\[ = - 3y \times xy + \left( - 3y \right) \times y^2 \]
\[ = - 3x y^{1 + 1} - 3 y^{1 + 2} \]
\[ = - 3x y^2 - 3 y^3\]
Substituting x = 4 and y = 5 in the result, we get:
\[- 3x y^2 - 3 y^3 \]
\[ = - 3\left( 4 \right) \left( 5 \right)^2 - 3 \left( 5 \right)^3 \]
\[ = - 3\left( 4 \right)\left( 25 \right) - 3\left( 125 \right)\]
\[ = - 300 - 375\]
\[ = - 675\]
Thus, the product is ( \[- 3x y^2 - 3 y^3\]), and its value for x = 4 and y = 5 is ( \[-\] 675).
संबंधित प्रश्न
Find each of the following product: \[\left( \frac{- 24}{25} x^3 z \right) \times \left( - \frac{15}{16}x z^2 y \right)\]
Find each of the following product:
\[\left( - \frac{1}{27} a^2 b^2 \right) \times \left( \frac{9}{2} a^3 b^2 c^2 \right)\]
Find the following product:
1.5x(10x2y − 100xy2)
Simplify: a(b − c) + b(c − a) + c(a − b)
Simplify: x2(x2 + 1) − x3(x + 1) − x(x3 − x)
Multiply:
(7x + y) by (x + 5y)
Multiply:
(x2 + y2) by (3a + 2b)
Multiply: \[\left( - \frac{a}{7} + \frac{a^2}{9} \right)by\left( \frac{b}{2} - \frac{b^2}{3} \right)\].
Find the following product and verify the result for x = − 1, y = − 2:
(3x − 5y) (x + y)
Simplify:
(3x + 2y)(4x + 3y) − (2x − y)(7x − 3y)
