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Find the Equation of the Normals to the Curve Y = X3 + 2x + 6 Which Are Parallel to the Line X + 14y + 4 = 0. - Mathematics

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Question

Find the equation of the normals to the curve y = x3 + 2+ 6 which are parallel to the line x + 14y + 4 = 0.

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Solution

The equation of the given curve is y = x3 + 2x + 6.

The slope of the tangent to the given curve at any point (xy) is given by,

When x = 2, y = 8 + 4 + 6 = 18.

When x = −2, y = − 8 − 4 + 6 = −6.

Therefore, there are two normals to the given curve with slope -1/4 and passing through the points (2, 18) and (−2, −6).

Thus, the equation of the normal through (2, 18) is given by,

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Chapter 6: Application of Derivatives - Exercise 6.3 [Page 213]

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NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 6 Application of Derivatives
Exercise 6.3 | Q 21 | Page 213

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