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Find the Equation of a Line for P = 4, α = 150°. - Mathematics

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Question

Find the equation of a line for p = 4, α = 150°.

Answer in Brief
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Solution

 Here, p = 4, α = 150°
So, the equation of the line in normal form is

\[x\cos {150}^\circ + y\sin {150}^\circ = 4\]

\[ \Rightarrow x\cos\left( 180^\circ - {30}^\circ \right) + y\sin\left( 180^\circ - {30}^\circ \right) = 4\]

\[ \Rightarrow - x\cos {30}^\circ + y\sin {30}^\circ = 4\]

\[ \Rightarrow - \frac{\sqrt{3}x}{2} + \frac{y}{2} = 4\]

\[ \Rightarrow \sqrt{3}x - y + 8 = 0\]

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Chapter 23: The straight lines - Exercise 23.7 [Page 53]

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RD Sharma Mathematics [English] Class 11
Chapter 23 The straight lines
Exercise 23.7 | Q 1.2 | Page 53
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