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Find the Equation of a Line for P = 4, α = 150°. - Mathematics

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प्रश्न

Find the equation of a line for p = 4, α = 150°.

संक्षेप में उत्तर
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उत्तर

 Here, p = 4, α = 150°
So, the equation of the line in normal form is

\[x\cos {150}^\circ + y\sin {150}^\circ = 4\]

\[ \Rightarrow x\cos\left( 180^\circ - {30}^\circ \right) + y\sin\left( 180^\circ - {30}^\circ \right) = 4\]

\[ \Rightarrow - x\cos {30}^\circ + y\sin {30}^\circ = 4\]

\[ \Rightarrow - \frac{\sqrt{3}x}{2} + \frac{y}{2} = 4\]

\[ \Rightarrow \sqrt{3}x - y + 8 = 0\]

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अध्याय 23: The straight lines - Exercise 23.7 [पृष्ठ ५३]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 23 The straight lines
Exercise 23.7 | Q 1.2 | पृष्ठ ५३
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