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Question
Find the equation of the hyperbola satisfying the given condition :
vertices (0, ± 5), foci (0, ± 8)
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Solution
The vertices of the hyperbola are \[\left( 0, \pm 5 \right)\] and the foci are \[\left( 0, \pm 8 \right)\] Thus, the value of \[a = 5\] and \[ae = 8\]
Now, using the relation
\[b^2 = a^2 ( e^2 - 1)\], we get:
\[\Rightarrow b^2 = 64 - 25\]
\[ \Rightarrow b^2 = 39\]
Thus, the equation of the hyperbola is \[- \frac{x^2}{39} + \frac{y^2}{25} = 1\].
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