Question

Find `dy/dx if x^3 + y^2 + xy = 7`

Answer 1

`x3 + y2 + xy = 7`
Differentiating both sides w.r.t.x.
`3x^2 + 2y dy/dx + x. dy/dx + y = 0`

`( 2y + x )dy/dx = -3x^2 - y`

`therefore dy/dx = [ - ( y + 3x^2 )]/[ 2y + x ]`