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Question
Find the distance of a point P(x, y) from the origin.
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Solution 1
Using distance formula
`l(OP) = sqrt((x-0)^2 + (y - 0)^2)`
`l(OP) = sqrt(x^2 -y^2)`
Solution 2
The given point is P(x, y).
The origin is O(0,0)
`PO = sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2) = sqrt((x-0)^2 + (y-0)^2) = sqrt(x^2 + y^2)`
Thus, the distance of point P from the origin is PO = `sqrt(x^2 + y^2)` units
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It is rectangular in shape - 100 yards by 60 yards. Goals consist of two upright posts placed equidistant from the centre of the backline, joined at the top by a horizontal crossbar. The inner edges of the posts must be 3.66 metres (4 yards) apart, and the lower edge of the crossbar must be 2.14 metres (7 feet) above the ground.
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The coordinates of the centroid of ΔEHJ are ______.
Read the following passage:
|
Alia and Shagun are friends living on the same street in Patel Nagar. Shagun's house is at the intersection of one street with another street on which there is a library. They both study in the same school and that is not far from Shagun's house. Suppose the school is situated at the point O, i.e., the origin, Alia's house is at A. Shagun's house is at B and library is at C. |
Based on the above information, answer the following questions.

- How far is Alia's house from Shagun's house?
- How far is the library from Shagun's house?
- Show that for Shagun, school is farther compared to Alia's house and library.
OR
Show that Alia’s house, shagun’s house and library for an isosceles right triangle.
