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Question
Find the dimensional formula of ε0.
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Solution
By Coulomb's Law, \[F = \frac{1}{4\pi \epsilon_0}\frac{q_1 q_2}{r^2}\]
[r] = [M0L1T0]
[q] = [M0L0T1A1], we get
[ε0] = [M−1L−3T4A2]
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