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Question
Find the coordinates of the point which is equidistant from the three vertices A (\[2x, 0) O (0, 0) \text{ and } B(0, 2y) of ∆\] AOB .
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Solution
It is known that, in a right angled triangle midpoint of the hypotenuse is equidistant from ots vertices.
Suppose D be the midpoint of the hypotenuse AB.
The coordinates of D are \[\left( \frac{2x + 0}{2}, \frac{0 + 2y}{2} \right) = \left( x, y \right)\] .
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