English

Find the Charge on the Capacitor as Shown in the Circuit.

Advertisements
Advertisements

Question

Find the charge on the capacitor as shown in the circuit.

Advertisements

Solution

Total current I through the circuit is given by

\[I = \frac{V}{R}\]
Here, V = 2 V
= (10+20) Ω = 30 Ω
\[\therefore I = \frac{2}{30} = \frac{1}{15} A\]
Voltage across 10 Ω resistor =\[I(10) = \frac{10}{15} = \frac{2}{3} V\]
∴ Charge on the capacitor is given by \[Q = CV = \left( 6 \times {10}^{- 6} \right)\left( \frac{2}{3} \right) = 4  \mu C\]
shaalaa.com
  Is there an error in this question or solution?
2013-2014 (March) Foreign Set 1

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Obtain the expression for the energy stored per unit volume in a charged parallel plate capacitor.


(a) Find the current in the 20 Ω resistor shown in the figure. (b) If a capacitor of capacitance 4 μF is joined between the points A and B, what would be the electrostatic energy stored in it in steady state?


A capacitance C, a resistance R and an emf ε are connected in series at t = 0. What is the maximum value of (a) the potential difference across the resistor (b) the current in the circuit (c) the potential difference across the capacitor (d) the energy stored in the capacitor (e) the power delivered by the battery and (f) the power converted into heat?


A 100 μF capacitor is joined to a 24 V battery through a 1.0 MΩ resistor. Plot qualitative graphs (a) between current and time for the first 10 minutes and (b) between charge and time for the same period.


How many time constants will elapse before the current in a charging RC circuit drops to half of its initial value? Answer the same question for a discharging RC circuit.


Choose the correct option:

Energy stored in a capacitor and dissipated during charging a capacitor bear a ratio.


A parallel plate condenser is immersed in an oil of dielectric constant 2. The field between the plates is ______.


A capacitor is charged by a battery and energy stored is 'U'. Now the battery is removed and the distance between plates is increased to four times. The energy stored becomes ______.


Electrostatic energy of 4 x 10−4 J is stored in a charged 25 pF capacitor. Find the charge on the capacitor.


If the charge on the parallel plate capacitor is increased by 3 C, the energy stored in it increases by 44%. The original charge on the capacitor is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×