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Find the angle between two vectors → a and → b with magnitudes 1 and 2 respectively and when ∣ ∣ → a × → b ∣ ∣ = √ 3 . - Mathematics

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Question

Find the angle between two vectors \[\vec{a} \text{ and }  \vec{b}\] with magnitudes 1 and 2 respectively and when \[\left| \vec{a} \times \vec{b} \right| = \sqrt{3} .\]

 
 
Short/Brief Note
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Solution

\[\text{ Let } \theta \text{ be the angle between } \vec{a} \text{ and } \vec{b} . \]
\[\text{ We know } \]
\[\left| \vec{a} \times \vec{b} \right| = \left| \vec{a} \right| \left| \vec{b} \right| \sin \theta\]
\[ \Rightarrow \sqrt{3} = \left( 1 \right) \left( 2 \right) \sin \theta\]
\[ \Rightarrow \sin \theta = \frac{\sqrt{3}}{2}\]
\[ \Rightarrow \theta = \frac{\pi}{3}\]

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Chapter 25: Vector or Cross Product - very short answers [Page 34]

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RD Sharma Mathematics [English] Class 12
Chapter 25 Vector or Cross Product
very short answers | Q 24 | Page 34

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