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Find a quadratic polynomial whose zeroes are 2 and –7/5.

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Question

Find a quadratic polynomial whose zeroes are 2 and `-7/5`.

Sum
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Solution

Given: The zeroes are 2 and `-7/5`.

Step-wise calculation:

1. Sum of zeroes = `2 + (-7/5) = 10/5 - 7/5 = 3/5`.

2. Product of zeroes = `2 xx (-7/5) = -14/5`.

3. A quadratic with roots α, β is x2 – (α + β)x + αβ.

4. Substitute the values: `x^2 - (3/5)x - 14/5`.

5. Multiply by 5 to clear fractions: 5x2 – 3x – 14.

A quadratic polynomial with the given zeroes is `x^2 - (3/5)x - 14/5` (monic). An integer-coefficient equivalent is 5x2 – 3x – 14.

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Chapter 2: Polynomials - VERY SHORT ANSWER TYPE QUESTIONS (VSAQS) [Page 2.50]

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R.D. Sharma Mathematics [English] Class 10
Chapter 2 Polynomials
VERY SHORT ANSWER TYPE QUESTIONS (VSAQS) | Q 30. | Page 2.50
R.D. Sharma Mathematics [English] Class 10
Chapter 2 Polynomials
VERY SHORT ANSWER TYPE QUESTIONS (VSAQS) | Q 9. (ii) | Page 2.49
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