Question

Figure shows a ray of light as it travels from medium A to medium B. Refractive index of the medium B relative to medium A is

Options

• `sqrt3//sqrt2`

• `sqrt2//sqrt3`

• `1//sqrt2`

• `sqrt2`

Answer 1

`sqrt3//sqrt2`

Explanation - 

Given :
Angle of incidence i = 60°, Angle of refraction r = 45°

Using snell's law we get,

Refractive index of medium B relative to medium A,

`"n"_("BA") = ("sin i")/("sin r")`

`= ("sin" 60)/("sin" 45)`

= `(sqrt3/2)/(1/sqrt2)`

= `sqrt3/sqrt2`