Advertisements
Advertisements
Question
Factorize each of the following expression:
2a5 − 32a
Advertisements
Solution
\[2 a^5 - 32a\]
\[ = 2a( a^4 - 16)\]
\[ = 2a[( a^2 )^2 - 4^2 ]\]
\[ = 2a( a^2 + 4)( a^2 - 4)\]
\[ = 2a( a^2 + 4)( a^2 - 2^2 )\]
\[ = 2a( a^2 + 4)(a + 2)(a - 2)\]
\[ = 2a(a - 2)(a + 2)( a^2 + 4)\]
RELATED QUESTIONS
Factorize each of the following expression:
25x4y4 − 1
Factorize each of the following expression:
\[\frac{1}{16} x^2 y^2 - \frac{4}{49} y^2 z^2\]
Factorize each of the following expression:
75a3b2 - 108ab4
Factorize each of the following expression:
Factorize each of the following expression:
x4 − 625
Factorize each of the following expression:
x4 − 1
Factorize each of the following expression:
49(a − b)2 − 25(a + b)2
Factorize each of the following expression:
16a4 − b4
Factorize each of the following quadratic polynomials by using the method of completing the square:
a2 + 2a − 3
Factorise: (7y2 – 19y – 6)
