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Question
Factorize each of the following algebraic expressions:
4(x + y) (3a − b) +6(x + y) (2b − 3a)
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Solution
\[4(x + y)(3a - b) + 6(x + y)(2b - 3a) \]
\[ = 2(x + y)[2(3a - b) + 3(2b - 3a)] {\text{ Taking }[2 (x + y)] \text{ as the common factor }}\]
\[ = 2(x + y)(6a - 2b + 6b - 9a)\]
\[ = 2(x + y)(4b - 3a)\]
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Match the following :
| Column A | Column B |
| (a) `x/2` = 10 | (i) x = 4 |
| (b) 20 = 6x − 4 | (ii) x = 1 |
| (c) 2x − 5 = 3 − x | (iii) x = 20 |
| (d) 7x − 4 − 8x = 20 | (iv) x = `8/3` |
| (e) `4/11 - x = (-7)/11` | (v) x = −24 |
