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Question
Factorize each of the following algebraic expression:
x2 + 14x + 45
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Solution
\[\text{ To factorise }x^2 + 14x + 45,\text{ we will find two numbers p and q such that }p + q = 14 \text{ and }pq = 45 . \]
Now,
\[9 + 5 = 14 \]
and
\[9 \times 5 = 45\]
\[\text{ Splitting the middle term }14x\text{ in the given quadratic as }9x + 5x,\text{ we get: }\]
\[ x^2 + 14x + 45 = x^2 + 9x + 5x + 45\]
\[ = ( x^2 + 9x) + (5x + 45)\]
\[ = x(x + 9) + 5(x + 9)\]
\[ = (x + 5)(x + 9)\]
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Match the following :
| Column A | Column B |
| (a) `x/2` = 10 | (i) x = 4 |
| (b) 20 = 6x − 4 | (ii) x = 1 |
| (c) 2x − 5 = 3 − x | (iii) x = 20 |
| (d) 7x − 4 − 8x = 20 | (iv) x = `8/3` |
| (e) `4/11 - x = (-7)/11` | (v) x = −24 |
