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Question
Factorize each of the following algebraic expression:
y2 + 5y − 36
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Solution
\[\text{ To factorise }y^2 + 5y - 36,\text{ we will find two numbers p and q such that }p + q = 5\text{ and }pq = - 36 . \]
Now,
\[9 + ( - 4) = 5 \]
and
\[9 \times ( - 4) = - 36\]
\[\text{ Splitting the middle term 5y in the given quadratic as } - 4y + 9y, \text{ we get: }\]
\[ y^2 + 5y - 36 = y^2 - 4y + 9y - 36\]
\[ = ( y^2 - 4y) + (9y - 36)\]
\[ = y(y - 4) + 9(y - 4)\]
\[ = (y + 9)(y - 4)\]
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Match the following :
| Column A | Column B |
| (a) `x/2` = 10 | (i) x = 4 |
| (b) 20 = 6x − 4 | (ii) x = 1 |
| (c) 2x − 5 = 3 − x | (iii) x = 20 |
| (d) 7x − 4 − 8x = 20 | (iv) x = `8/3` |
| (e) `4/11 - x = (-7)/11` | (v) x = −24 |
