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Question
Factorise:
x6 – 124x3 – 125
Sum
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Solution
To factorise x6 – 124x3 – 125, let’s first treat this expression as a quadratic in terms of x3.
Let y = x3.
The expression becomes:
y2 – 124y – 125
Now, factor the quadratic expression:
y2 – 124y – 125 = (y – 125) (y + 1)
Substitute y = x3 back into the factored expression:
(x3 – 125) (x3 + 1)
Both of these terms are differences and sums of cubes:
x3 – 125 = (x – 5) (x2 + 5x + 25)
x3 + 1 = (x + 1) (x2 – x + 1)
Thus, the fully factorised form of x6 – 124x3 – 125 is (x – 5) (x + 1)(x2 + 5x + 25) (x2 – x + 1)
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